Given an integer n, return true if it is a power of three. Otherwise, return false.
n
true
false
An integer n is a power of three, if there exists an integer x such that n == 3x.
x
n == 3x
Example 1:
Input: n = 27 Output: true
Example 2:
Input: n = 0 Output: false
Example 3:
Input: n = 9 Output: true
Constraints:
-231 <= n <= 231 - 1
Follow up: Could you solve it without loops/recursion?
Last updated 3 years ago
class Solution: def isPowerOfThree(self, n: int) -> bool: return n > 0 and (log10(n)/log10(3)).is_integer()