# 231. Power of Two

## Easy

***

Given an integer `n`, return *`true` if it is a power of two. Otherwise, return `false`*.

An integer `n` is a power of two, if there exists an integer `x` such that `n == 2x`.

**Example 1:**

```
Input: n = 1
Output: true
Explanation: 20 = 1
```

**Example 2:**

```
Input: n = 16
Output: true
Explanation: 24 = 16
```

**Example 3:**

```
Input: n = 3
Output: false
```

**Example 4:**

```
Input: n = 4
Output: true
```

**Example 5:**

```
Input: n = 5
Output: false
```

**Constraints:**

* `-231 <= n <= 231 - 1`

**Follow up:** Could you solve it without loops/recursion?

```python
class Solution:
    def isPowerOfTwo(self, n: int) -> bool:
        if n <= 0:
            return False
        return (math.log10(n) / math.log10(2)).is_integer()
```