1015. Smallest Integer Divisible by K
Medium
Given a positive integer k
, you need to find the length of the smallest positive integer n
such that n
is divisible by k
, and n
only contains the digit 1
.
Return the length of n
. If there is no such n
, return -1.
Note: n
may not fit in a 64-bit signed integer.
Example 1:
Input: k = 1
Output: 1
Explanation: The smallest answer is n = 1, which has length 1.
Example 2:
Input: k = 2
Output: -1
Explanation: There is no such positive integer n divisible by 2.
Example 3:
Input: k = 3
Output: 3
Explanation: The smallest answer is n = 111, which has length 3.
Constraints:
1 <= k <= 105
class Solution:
def smallestRepunitDivByK(self, k: int) -> int:
num = 0
for i in range(k):
num = num*10 + 1
if num%k == 0:
return len(str(num))
return -1
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