# 1249. Minimum Remove to Make Valid Parentheses

#### Medium

***

Given a string s of `'('` , `')'` and lowercase English characters.

Your task is to remove the minimum number of parentheses ( `'('` or `')'`, in any positions ) so that the resulting *parentheses string* is valid and return **any** valid string.

Formally, a *parentheses string* is valid if and only if:

* It is the empty string, contains only lowercase characters, or
* It can be written as `AB` (`A` concatenated with `B`), where `A` and `B` are valid strings, or
* It can be written as `(A)`, where `A` is a valid string.

 

**Example 1:**

```
Input: s = "lee(t(c)o)de)"
Output: "lee(t(c)o)de"
Explanation: "lee(t(co)de)" , "lee(t(c)ode)" would also be accepted.
```

**Example 2:**

```
Input: s = "a)b(c)d"
Output: "ab(c)d"
```

**Example 3:**

```
Input: s = "))(("
Output: ""
Explanation: An empty string is also valid.
```

 

**Constraints:**

* `1 <= s.length <= 105`
* `s[i]` is either`'('` , `')'`, or lowercase English letter`.`

```python
class Solution:
    def minRemoveToMakeValid(self, s: str) -> str:
        left_index = []
        right_index = []
        for index, char in enumerate(list(s)):
            if char == "(":
                left_index.append(index)
            elif char == ")":
                if left_index and left_index[-1] < index:
                    left_index.pop()
                else:
                    right_index.append(index)
        array = list(s)
        left_index.extend(right_index)
        return "".join([char for idx, char in enumerate(array) if idx not in left_index])
                
                        
```