147. Insertion Sort List
Medium
Given the head
of a singly linked list, sort the list using insertion sort, and return the sorted list's head.
The steps of the insertion sort algorithm:
Insertion sort iterates, consuming one input element each repetition and growing a sorted output list.
At each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list and inserts it there.
It repeats until no input elements remain.
The following is a graphical example of the insertion sort algorithm. The partially sorted list (black) initially contains only the first element in the list. One element (red) is removed from the input data and inserted in-place into the sorted list with each iteration.

Example 1:

Input: head = [4,2,1,3]
Output: [1,2,3,4]
Example 2:

Input: head = [-1,5,3,4,0]
Output: [-1,0,3,4,5]
Constraints:
The number of nodes in the list is in the range
[1, 5000]
.-5000 <= Node.val <= 5000
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def insertionSortList(self, head: Optional[ListNode]) -> Optional[ListNode]:
dummy = ListNode(0, head)
node = head.next
head.next = None
while node:
next_node = node.next
ptr = dummy
# note that we are creating reverse list here just like insertion order
while ptr.next and ptr.next.val > node.val:
ptr = ptr.next
node.next = ptr.next
ptr.next = node
node = next_node
node = dummy.next
head = None
# Simple Reversing
while node:
next_node = node.next
node.next = head
head = node
node = next_node
return head
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