# 991. Broken Calculator

#### Medium

***

There is a broken calculator that has the integer `startValue` on its display initially. In one operation, you can:

* multiply the number on display by `2`, or
* subtract `1` from the number on display.

Given two integers `startValue` and `target`, return *the minimum number of operations needed to display* `target` *on the calculator*.

 

**Example 1:**

```
Input: startValue = 2, target = 3
Output: 2
Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.
```

**Example 2:**

```
Input: startValue = 5, target = 8
Output: 2
Explanation: Use decrement and then double {5 -> 4 -> 8}.
```

**Example 3:**

```
Input: startValue = 3, target = 10
Output: 3
Explanation: Use double, decrement and double {3 -> 6 -> 5 -> 10}.
```

 

**Constraints:**

* `1 <= x, y <= 109`

```python
class Solution:
    def brokenCalc(self, startValue: int, target: int) -> int:
        # Instead of subtract and multiply do add and divide.
        # For Division we need to have even 
        operations = 0
        while target > startValue:
            operations += 1
            if target % 2 == 1:
                target += 1
            else:
                target = target // 2
        return operations + (startValue-target)
```