784. Letter Case Permutation
Medium
Input: s = "a1b2"
Output: ["a1b2","a1B2","A1b2","A1B2"]Input: s = "3z4"
Output: ["3z4","3Z4"]Input: s = "12345"
Output: ["12345"]Input: s = "0"
Output: ["0"]Last updated
Input: s = "a1b2"
Output: ["a1b2","a1B2","A1b2","A1B2"]Input: s = "3z4"
Output: ["3z4","3Z4"]Input: s = "12345"
Output: ["12345"]Input: s = "0"
Output: ["0"]Last updated
class Solution:
def letterCasePermutation(self, s: str) -> List[str]:
s = s.lower()
result = set()
def recursion(s, ele, start, result):
if start >= len(s):
result.add(ele)
return
for index in range(start, len(s)):
recursion(s, ele[:index] + ele[index].upper() + ele[index+1:], index+1, result)
recursion(s, ele, index+1, result)
recursion(s,s,0, result)
return list(result)