383. Ransom Note

Easy

---

Given two strings ransomNote and magazine, return true if ransomNote can be constructed by using the letters from magazine and false otherwise.

Each letter in magazine can only be used once in ransomNote.

Example 1:

Input: ransomNote = "a", magazine = "b"
Output:
 false

Example 2:

Input: ransomNote = "aa", magazine = "ab"
Output:
 false

Example 3:

Input: ransomNote = "aa", magazine = "aab"
Output:
 true

Constraints:

• 1 <= ransomNote.length, magazine.length <= 105

• ransomNote and magazine consist of lowercase English letters.

class Solution:
    def canConstruct(self, ransomNote: str, magazine: str) -> bool:
        counterA = self.getDict(ransomNote)
        counterB = self.getDict(magazine)
        for key in counterA.keys():
            if counterB[key] < counterA[key]:
                return False
        return True
    
    def getDict(self, s: str):
        d = defaultdict(int)
        for char in list(s):
            d[char] += 1
        return d