393. UTF-8 Validation
Medium
Given an integer array data
representing the data, return whether it is a valid UTF-8 encoding (i.e. it translates to a sequence of valid UTF-8 encoded characters).
A character in UTF8 can be from 1 to 4 bytes long, subjected to the following rules:
For a 1-byte character, the first bit is a
0
, followed by its Unicode code.For an n-bytes character, the first
n
bits are all one's, then + 1
bit is0
, followed byn - 1
bytes with the most significant2
bits being10
.
This is how the UTF-8 encoding would work:
Number of Bytes | UTF-8 Octet Sequence
| (binary)
--------------------+-----------------------------------------
1 | 0xxxxxxx
2 | 110xxxxx 10xxxxxx
3 | 1110xxxx 10xxxxxx 10xxxxxx
4 | 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx
x
denotes a bit in the binary form of a byte that may be either 0
or 1
.
Note: The input is an array of integers. Only the least significant 8 bits of each integer is used to store the data. This means each integer represents only 1 byte of data.
Example 1:
Input: data = [197,130,1]
Output:
true
Explanation:
data represents the octet sequence: 11000101 10000010 00000001.
It is a valid utf-8 encoding for a 2-bytes character followed by a 1-byte character.
Example 2:
Input: data = [235,140,4]
Output:
false
Explanation:
data represented the octet sequence: 11101011 10001100 00000100.
The first 3 bits are all one's and the 4th bit is 0 means it is a 3-bytes character.
The next byte is a continuation byte which starts with 10 and that's correct.
But the second continuation byte does not start with 10, so it is invalid.
Constraints:
1 <= data.length <= 2 * 104
0 <= data[i] <= 255
class Solution:
def validUtf8(self, data: List[int]) -> bool:
data = [str(bin(seq)[2:].zfill(8)) for seq in data]
while data:
seq = data.pop(0)
if seq.startswith("0"): continue
if seq.startswith("110"):
if not self.rest(data, 1): return False
elif seq.startswith("1110"):
if not self.rest(data, 2): return False
elif seq.startswith("11110"):
if not self.rest(data, 3): return False
else: return False
return True
def rest(self, data, i):
if len(data) < i: return False
for _ in range(i):
if not data.pop(0).startswith("10"): return False
return True
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